1Z1-071 ACCURATE TEST - 1Z1-071 TEST QUESTIONS PDF

1z1-071 Accurate Test - 1z1-071 Test Questions Pdf

1z1-071 Accurate Test - 1z1-071 Test Questions Pdf

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Oracle Database SQL Sample Questions (Q35-Q40):

NEW QUESTION # 35
Which two statements are true about sequences crated in a single instance Oracle database?

  • A. CURRVAL is used to refer to the most recent sequence number that has been generated for a particular sequence.
  • B. When the MAXVALUE limit for a sequence is reached, it can be increased by using the ALTER SEQUENCE statement.
  • C. When the database instance shuts down abnormally, sequence numbers that have been cached but not used are available again when the instance is restarted.
  • D. DELETE <sequencename> would remove a sequence from the database.
  • E. The numbers generated by an explicitly defined sequence can only be used to insert data in one table.

Answer: A,B


NEW QUESTION # 36
View the exhibit and examine the description of the DEPARTMENTSand EMPLOYEEStables.

The retrieve data for all the employees for their EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, the following SQL statement was written:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?

  • A. The DEPARTMENTStable is not used before the EMPLOYEEStable in the FROMclause.
  • B. The NATURAL JOINclause is missing the USINGclause.
  • C. The table prefix is missing for the column names in the SELECTclause.
  • D. The EMPLOYEESand DEPARTMENTStables have more than one column with the same column name and data type.

Answer: D

Explanation:
Explanation/Reference:
Explanation:
Natural join needs only one column to be the same in each table. The EMPLOYEESand DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID)


NEW QUESTION # 37
The CUSTOMERStable has a CUST_CREDIT_LIMITcolumn of data type NUMBER.
Which two queries execute successfully? (Choose two.)

  • A. SELECT NVL(TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;
  • B. SELECT NVL (cust_credit_limit * .15, 'Not Available') FROM customers;
  • C. SELECT TO_CHAR(NVL(cust_credit_limit * .15, 'Not Available')) FROM customers;
  • D. SELECT NVL2(cust_credit_limit, TO_CHAR(cust_credit_limit * .15), 'Not
  • E. Available') FROM customers;
    SELECT NVL2 (cust_credit_limit * .15, 'Not Available') FROM customers;

Answer: A,E


NEW QUESTION # 38
Examine the business rule:
Each student can work on multiple projects and each project can have multiple students.
You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:
STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME PROJECT_TASK
Which two statements are true in this scenario? (Choose two.)

  • A. The ERD must have a M:M relationship between the STUDENTS and PROJECTS entities that must be resolved into 1:M relationships.
  • B. STUDENT_ID must be the primary key in the STUDENTS entity and foreign key in the PROJECTS entity.
  • C. An associative table must be created with a composite key of STUDENT_ID and PROJECT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.
  • D. PROJECT_ID must be the primary key in the PROJECTS entity and foreign key in the STUDENTS entity.
  • E. The ERD must have a 1:M relationship between the STUDENTS and PROJECTS entities.

Answer: A,C

Explanation:
References:
http://www.oracle.com/technetwork/issue-archive/2011/11-nov/o61sql-512018.html


NEW QUESTION # 39
Refer to the exhibit.

Which two queries only return CUBE?

  • A. SELECT shape FROM bricks JOIN boxes ON weight < max_weight;
  • B. SELECT shape FROM bricks JOIN boxes ON weight > min_weight;
  • C. SELECT shape FROM bricks JOIN boxes ON weight BETWEEN min_weight AND max_weight;
  • D. SELECT shape FROM bricks JOIN boxes ON weight >= min_weight AND weight < max_weight;
  • E. SELECT shape FROM bricks JOIN boxes ON NOT (weight > max_weight);

Answer: D,E

Explanation:
Based on the table structure given in the image, to return the value 'CUBE' from the 'bricks' table when joined with 'boxes', the condition must ensure that the weight of the bricks is within the allowed weight range specified in the 'boxes' table for a 'SMALL' box size.
A . True. Since MAX_WEIGHT is 0, a comparison using >= min_weight AND weight < max_weight will only return rows where the weight is less than 0, which is impossible for actual weight values, suggesting there might be a mistake in the data provided or the comparison logic.
E . True. NOT (weight > max_weight) effectively translates to 'where weight is less than or equal to max_weight'. However, since MAX_WEIGHT is 0, this condition would only be true if the weight is not greater than 0, which can only happen if the weight is 0 or less. This seems to indicate an anomaly where either the data is incorrect, or the condition is meant to handle a case where the weight is zero or possibly a negative placeholder value.
Both B and D will potentially return more than just 'CUBE' if there are bricks with weights greater than MIN_WEIGHT. C is incorrect because BETWEEN is inclusive, and there are no weights that are both greater than or equal to MIN_WEIGHT and less than or equal to MAX_WEIGHT when MAX_WEIGHT is 0.


NEW QUESTION # 40
......

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